Ramani borrows Rs.25000 for 180 days at 9% of annual interest compounded daily. How much will she owe at the end of 180 days?

Amount (A) = Rs. 26,134.43819

Step-by-step explanation:

Ramani borrows Rs. 25,000 for 180 days at 9% annual interest compounded daily.

Principal (P) = Rs. 25,000

Rate (r) = 9% annual interest = 0.09

Number of times interest applied per year (n) = 365 days

Number of time periods in 1 year (t) = 180/365

Compound interest formula;

Amount (A) = P(1 +

A = 25,000(1 + = Rs. 26,134.43819

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

dont know

step-by-step explanation: