Mathematics, 05.09.2020 02:01 laniflower737
The temperature at 5:00 a. m. was –6 °F. By 3:00 p. m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p. m. decreased from the high by of the change in temperature in Fahrenheit degrees from 5:00 a. m. to 3:00 p. m., what was the temperature at 8:00 p. m.?
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Mathematics, 21.06.2019 22:00, juniorracer148
For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
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The temperature at 5:00 a. m. was –6 °F. By 3:00 p. m., the temperature had risen to a high of 36 °F...
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