The sum of two consecutive integers is 345. What are the integers? need help with it

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Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 345

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 345

3X + 3 = 345

3X + 3 - 3 = 345 - 3

3X = 342

3X/3 = 342/3

X = 114

Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.

114 + 115 + 116 = 345

We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.

Step-by-step explanation:

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x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

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plug in the numbers into the variables

your answer is a

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step-by-step explanation: