Find the indicated angle. Round your answer to the nearest tenth. Part 2. Show work please

 5) 72.6°      6) 68.7°       7) 37.3°        8) 81.5°

Step-by-step explanation:

Law of Cosines:    a² = b² + c² - 2bc · cos A

                              b² = a² + c² - 2ac · cos B

                              c² = a² + b² - 2ab · cos C

5) a = 27, b = 26, c = 20, A = ???

   a² = b² + c² - 2bc · cos A

27² = 26² + 20² - 2(26)(20) · cos A

729 = 676 + 400 - 1040 cos A

729 = 1076 - 1040 cos A

-311 = -1040 cos A

72.6° = A

6) a = 11, b = 13, c = 12, B = ???

   b² = a² + c² - 2ac · cos B

13² = 11² + 12² - 2(11)(12) · cos B

169 = 121 + 144 - 264 cos B

169 = 265 - 264 cos B

-96 = -264 cos B

68.7° = B

7) a = 19.2, b = 11.7, c = 16.5, B = ???

   b² = a² + c² - 2ac · cos B

11.7² = 19.2² + 16.5² - 2(19.2)(16.5) · cos B

136.89 = 368.64 + 272.25 - 633.6 cos B

136.89 = 640.89 - 633.6 cos B

-504 = -633.6 cos B

37.3° = B

8) a = 8.8, b = 12.4, c = 14.1, C = ???

   c² = a² + b² - 2ab · cos C

14.1² = 8.8² + 12.4² - 2(8.8)(12.4) · cos C

198.81 = 77.44 + 153.76 - 218.24 cos C

198.81 = 231.2 - 218.24 cos C

-32.39 = -218.24 cos C

81.5° = C

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.