What is the density of an object with 17 g and a volume of 3cm^3

5.6666666666667 grams/cubic centimeters

Step-by-step explanation:

teps:

ρ =    m / v

17 gram s / 3 cubic centimeter

=  5.6666666666667 grams/cubic centimeter

I believe this is correct unless you need to round it up

I hope I helped

5.67g/cm³

Step-by-step explanation:

Density =mass ÷ volume

17÷3=5.67

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

14

step-by-step explanation: