Tentukan nilai x yang memenuhi ketidaksamaan. |3x + 12| < 2 |x - 6|

Step-by-step explanation:

|3x + 12| < 2 |x - 6|

|3(x + 4)| < 2 |x - 6|        ⇒  -4 and 6 are "zeros"

1°.  x∈(-∞, -4> ⇒ |3x + 12| = - (3x + 12)  and  2|x - 6| = -2(x-6)

-(3x + 12) < -2(x - 6)

-3x - 12 < -2x + 12

  -x < 24

x > -24  ∧ x∈(-∞-4> ⇒ x∈(-18, -4>

2°.  x∈(-4, 6)  ⇒ |3x + 12| = 3x+12  and  2|x - 6| = -2(x-6)

3x + 12 < -2(x - 6)

3x + 12 < -2x + 12

  5x < 0

x < 0  ∧ x∈(-4, 6)  ⇒ x∈(-4, 0)

3°.  x∈(6, ∞)  ⇒ |3x + 12| = 3x+12  and  2|x - 6| = 2(x-6)

3x + 12 < 2(x - 6)

3x + 12 < 2x - 12

  x < -24

x < -24  ∧  x∈(6, ∞)  ⇒ x∈∅

x∈1°∪2°∪3°

x∈(-24, -4>∪(-4, 0)∪∅

x∈(-24, 0)   ⇒   -24 < x < 0

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.