Does every quadratic equation have at least one real solution? Explain. (1 point)
A. Yes. When the discriminant is zero, there is exactly one solution. When the discriminant is not zero, there are two unique solutions.
B. No. When the discriminant is greater than zero, there are no real solutions.
C. Yes. When the discriminant is zero, there are two unique solutions. When the discriminant is not zero, there is exactly one solution.
D. No. When the discriminant is less than zero, there are no real solutions.

D. No. When the discriminant is less than zero, there are no real solutions.

Step-by-step explanation:

We have to notice that quadratic equations are second order polynomials whose standard form is:

,

The factorized form of this polynomial is:

Where and are the roots of the quadratic equation, which may be real or complex.

If we equalize to zero and make algebraic handling, we can get the value of each root anatically by the Quadratic Formula:

Where is known as the discriminant. Then, we should remember the following rules:

i) If discriminant is greater than zero, then the quadratic equation has two different real roots.

ii) If discriminant is zero, then the quadratic equation has two equal real roots.

iii) If discriminant is less than zero, then the quadratic function has two complex roots.

In consequence, we came to the conclusion that statement is false, as quadratic equation have all roots real or all complex, but not one real and the other complex.

In a nutshell, the correct answer is D.

the k side

step-by-step explanation:

plese mark mde brainliest!

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.