Mathematics, 04.09.2020 05:01 rosie20052019

In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D,$ such that $AD = AB$. Line segment $\overline{AD}$ is extended to $E,$ such that $CD = CE$ and $\angle DBE = \angle BAD$. Show that triangle $ACE$ is isosceles.

$In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D,$ such that $AD =$

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In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D,$ such that $AD =...