PLEASE HELP I HAVE 30 POINTS Part A: If (6^2)^x = 1, what is the value of x? Explain your answer. (5 points) Part B: If (6^0)^x = 1, what are the possible values of x? Explain your answer. (5 points)

Part A: 0

Part B: All real numbers

Step-by-step explanation:

Part A:

We have:

First, let's evaluate the square:

Now, what to the xth power will equal 1?

Remember the fact that anything (except for 0) to the zeroth power is 1.

Therefore, our x is 0:

Part B:

We have:

Like mentioned previously, anything to the zeroth power is 1. Thus:

Now, 1 is a special base because 1 to any (real) power is still going to be 1. For example:

Therefore, our values of x is all real numbers.

And we're done!

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions