A coin flipped 10 times and the results is recorded. What is the probability of getting at least 8 tails ?

0.0546875

Step-by-step explanation:

The number of times the coin landing head 8 out of 10 is simply:

C(10, 8)/2^10. At least 8 means, 8 or more. Since the events here are dependent on themselves the answer would be:

[ C(10, 8) + C(10, 9) + C(10, 10) ] / 2^10 = 56/1024 = 0.0546875

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x