How do you solve this

4x^-4/9y^6

Step-by-step explanation:

If the exponent is outside the bracket, it means that all the terms inside will be raised to that exponent. This means that:

(2x^-2 / 3y^3)^2 = 2^2*(x^-2)^2 / 3^2*(y^3)^2

When exponents are raised to an exponent, the exponents are multiplied together, so (x^-2)^2 will = x^(-2*2) = x^-4

Going through:

2^2*(x^-2)^2 / 3^2*(y^3)^2

=4*x^-4 / 9*y^6

=4x^-4/9y^6

Hope this helped!

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

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