3. What are the coordinates of the centroid of a triangle with vertices at

Q (1,0), R (-10,-6), and S (0, -6)?

coordinates for the centroid is at (-3, -4)

Step-by-step explanation:

The centroid of a triangle is simply defined as the center point which is equidistant from the three vertices.

Let's denote the centroid as O. Thus, the coordinates of O will be: (O_x, O_y).

Now, the formula to calculate the centroid of a triangle with coordinates (O_x, O_y) is given by;

For x - coordinate;

O_x = (A_x + B_x + C_x)/3

For y - coordinate;

O_y = (A_y + B_y + C_y)/3

From the question,

A_x = 1

B_x = -10

C_x = 0

A_y = 0

B_y = -6

C_y = -6

Thus;

O_x = (1 - 10 + 0)/3

O_x = -9/3

O_x = -3

Also,

O_y = (0 - 6 - 6)/3

O_y = - 12/3

O_y = - 4

Thus, coordinates for the centroid is at (-3, -4)

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225