The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π). 2sin2x+sinx=1

Step-by-step explanation:

Given the quadratic equation as:

Let us put for simplicity of the equation:

Now, the equation becomes:

Now, let us try to solve the quadratic equation:

So, the solution to the given trigonometric quadratic equation is:

and

Let us try to find the values of in the interval .

can have a value equal to in 1st and 2nd quadrant.

So, can be

For ,

So, the answer is:

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)