A cylindrical can has a volume of 16 cm 3. What dimensions yield the minimum surface area? 1. The radius of the can with the minimum surface area is cm. (Simplify your answer.) 2. The height of the can with the minimum surface area is cm. (Simplify your answer.)

radius = 1.37 cm

height = 2.71 cm

Step-by-step explanation:

We are given volume = 16 m³.

Formula for volume of a cylinder is;

V = πr²h

Thus,

πr²h = 16

h = 16/πr²

Now formula for the surface area is;

S = 2πr² + 2πrh

Putting 16/πr² for h gives;

S = 2πr² + 2πr(16/πr²)

S = 2πr² + 2π(16/πr)

S = 2π(r² + 16/πr)

To minimize, we will find the derivative of S and equate to zero

S' = 2π(2r - 16/πr²) = 0

4πr - 32/r² = 0

4πr = 32/r²

r³ = 32/4π

r = ∛(32/4π)

r = 1.37 cm

From h = 16/πr²;

h = 16/(π × 1.37²)

h = 2.71 cm

well

44-3-3-3=35

35+4+4+4+4=51

so the ansewr would be 51 degreesat 7: 00

my answer was deleted because it was to vague the answer is 12.76 becuase its in the hundreths place. john