Jeremy is painting his room over the summer. Here are 4 different wall
colors and 3 different trim colors.
How many different ways can he
paint his room?

12 different ways

Step-by-step explanation:

The question is asking for a combination of a wall color and a trim color because his room required one wall color and one trim color.

In this case, combination will be the number of first kind multiplies with the second kind. This is similar to sketching a tree diagram but instead, we will be using numerical method which will be quicker.

If you are still confused, I will provide some examples.

This also applies to your question. You have 4 different wall colors and 3 different trim colors.

4×3=12

You have 12 different ways to paint the room

Hope this helps!! :)

Please let me know if you have any question

answer: the correct answer is -32

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.