HLP11 I WILL MARK BRAINLIEST kx-3y=4 4x-5y=7 k is constant and x and y are variables, for what value of k will the system of equations have NO SOLUTION??? A. 12/5 B. 16/7 C. -16/7 D. -12/5 also side question, how do you find out if an equation has 1 solution or no solution or infinite solutions???

Step-by-step explanation:

There is no solution for system of equations:  

if:    

so first, we we need to transform the equations to the form where the coefficients at y will be the same:

Now we have  b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂

5k = 12

÷5     ÷5

k = ¹²/₅

i can

step-by-step explanation:

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]