A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 16 of the pole is in the ground, 23 of the pole is covered in snow, and 1.8 ft is above the snow. How long is the pole, and how deep is the snow

Length of the pole = 10.8 ft

Depth of the snow = 7.2 ft

Step-by-step explanation:

The correct question is

A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 1/6 of the pole is in the ground, 2/3 of the pole is covered in snow, and 1.8 ft is above the snow. How long is the pole, and how deep is the snow.

The fraction of the pole in the ground = 1/6

The fraction of the pole in the snow = 2/3

The length of the pole above the snow = 1.8 ft

Total fraction of the length of the pole = 1

For the fraction of the length above the snow, we solve as

1/6 + 2/3 + = 1

= 1 - 1/6 - 2/3 = 1/6

This means that the length of the pole above the snow 1.8 ft = 1/6 of the length of the pole.

Also, the fraction of the pole in the ground = 1/6

this means that the length of the pole in the ground = 1.8 ft

If 1/6 of the length of pole is 1.8 ft,

the length of the pole = 1.8 ft x 6 = 10.8 ft

Length of the pole in the snow = 2/3 of 10.8 = 2/3 x 10.8 = 7.2 ft

this means that the the snow is 7.2 ft deep

step-by-step explanation:

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: