Which of the following were members of the aristocracy in byzantine society? a) shopkeepers
b) small scale merchants
c) soldiers
d) wealthy landowners

7

step-by-step explanation:

answer: 8

step-by-step explanation:

there were a lot of them but the first one to pop up on a google search was bts

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .