If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.Find the sum of all the multiples of 3 or 5 below 1000.

Given :

All the natural numbers below 1000 that are multiples of 3 or 5 .

To Find :

The sum of all the multiples of 3 or 5 below 1000.

Solution :

Max multiple of 3 is 999 .

Max multiple of 5 id 995 .

So , number of multiple of 3 is :

Similarly for 5 .

Now , sum of all multiple of 3 is given by :

Also , sum of all multiple of 5 is :

Therefore , total sum :

Now , there are some common number which we add two times like :

15 , 30 , 60 ......

So , we should subtract the sum of all multiple of 15 from T .

Now , sum of all multiple of 15 is 33165 .

So ,

Therefore , the  sum of all the multiples of 3 or 5 below 1000 is 233168 .

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for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for