What is 45,231 written in expanded form? 2 x 10,000 + 1 x 1,000 + 3 x 100 + 5 x 10 + 4 2 x 10,000 + 3 x 1,000 + 1 x 100 + 4 x 10 + 5 3 x 10,000 + 4 x 1,000 + 5 x 100 + 1 x 10 + 2 4 x 10,000 + 5 x 1,000 + 2 x 100 + 3 x 10 + 1 x 1

45231 =

Step-by-step explanation:

Given the number:

45,231

We have To write the given number in the expanded form.

Solution:

First of all, let us write the different digits of the number:

Unit's digit = 1

Ten's digit = 3

Hundred's digit = 2

Thousand's digit = 5

Ten thousand's digit = 4

Unit's digit has to be multiplied with 1.

Ten's digit has to be multiplied with 10.

Hundred's digit has to be multiplied with 100.

Thousand's digit has to be multiplied with 1000.

Ten Thousand's digit has to be multiplied with 10000.

And then they have to be added so that the number gets formed.

45231 =

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

b.my answer is b.

brainliest