WILL MARK BRAINLIEST Convert 5.4 ⋅ 103 to standard form.
A. 0.0054
B. 0.00054
C. 5,400
D. 54,000

5400

Step-by-step explanation:

Convert 5.4 ⋅ 103 to standard form.

for 10^3 we add 3 zeros

10^3= 10 times 10 times 10=1000

Replace 10^3 by 1000. then multiply with the decimal number

When we multiply by 1000 we move the decimal point 3 places to the right

5400

I hope this helps u! :D

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!