Can someone help me find the answer to these 3 problems if so thank you .

1. r+s²=49

2. pq²=24

3. -4xy-6x²+2x²y-6y= -54

Step-by-step explanation:

1. r+s²=0+7²=49

2. pq²=(6)(2)²=6(4)=24

3. -4xy-6x²+2x²y-6y= -4(3)(2)-6(3)²+2(3)²(2)-6(2)

                                = -24-6(9)+2(9)(2)-12

                                = -24-54+36-12

                                = -78+36-12

                                = -42-12

                                = -54

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )