Mathematics, 28.08.2020 22:01 srshelton
Find the partial derivative of the function f(x, y)=Integral of cos(-7t^2-6t-1)dt. Find fx(x, y) and fy(x, y)
Answers: 2
![\dfrac{\partial f}{\partial x}= \dfrac{\partial }{\partial x} [ \int ^x_y cos (-7t^2 -6t -1 ) \ dt]](/tpl/images/0733/1069/3453c.png)
![\dfrac{\partial f}{\partial x}= \dfrac{\partial x}{\partial x} cos (-7x^2 -6x -1 ) - \dfrac{\partial y}{\partial x} * cos (-7y^2 -6y-1) + \int ^x_y [\dfrac{\partial }{\partial x} \ \{cos (-7t^2-6t-1)\}] \ dt](/tpl/images/0733/1069/cca1c.png)
![\dfrac{\partial f}{\partial y}= \dfrac{\partial }{\partial y} [ \int ^x_y cos (-7t^2 -6t -1 ) \ dt]](/tpl/images/0733/1069/8d034.png)
![\dfrac{\partial f}{\partial y}= \dfrac{\partial x}{\partial y} cos (-7x^2 -6x -1 ) - \dfrac{\partial y}{\partial y} * cos (-7y^2 -6y-1) + \int ^x_y [\dfrac{\partial }{\partial y} \ \{cos (-7t^2-6t-1)\}] \ dt](/tpl/images/0733/1069/ac27c.png)
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Find the partial derivative of the function f(x, y)=Integral of cos(-7t^2-6t-1)dt. Find fx(x, y) and...
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