Help me with this.. thanks

Attachment 1 :-   x = 3/2

Attachment 2 :-  m + r = 154°

Step-by-step explanation:

Attachment 1 :-

As the base 3 is same on both the sides , cancel the base 3 from both left & right side of eqn. After that we will get:-

Attachment 2 :-

PQR is a straight line . It's given that m + n = 110°

But we know that m + n + r = 180° ..............eqn.1

So substituting the value of m+n in eqn.1 gives :-

m+n+r = 180°

=> r + 110° = 180°

=> r = 180° - 110°

       = 70°

It's also given that n+r = 96°

So putting the value of r in the above gives ,

n+r = 96°

=> n + 70° =96°

=> n = 96° - 70°

        = 26°

Putting the value of n in eqn.1 gives

m + n = 110°

=> m + 26° = 110°

=> m = 110° - 26°

        = 84°

So m + r = 84° + 70° = 154°

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0