The area of a rectangle is (x2 - 5x - 36). What is the width if the length of the rectangle is (x + 4)?

Step-by-step explanation:

The width of the rectangle is (x - 9)

(x + 4)(x - 9)

x^2 - 9x + 4x - 36

x^2 - 5x - 36

W = ( x - 9 )

Step-by-step explanation:

The area of a rectangle is equal to the length times the width of the rectangle.

So we can say A = LW

A = (x^2 - 5x - 36)

L = (x + 4)

A = LW

W = A / L

W = (x^2 - 5x - 36) / (x + 4)

W = (x + 4) (x - 9) / (x + 4)

W = (x - 9)

Cheers.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet