Which piecewise function is shown in the graph? ty
fx) = {
-0.5 x + 1, x < 0
2x - 2,
x ΣΟ
4
f(x) =
2
--x + 1, x < 0
0.5 x 2, x > 0
x
xso
O fx) = (x - 1
2x - 2, x > 0
-4
-2
2.
4
-2
f(x) = -0.5x - 1, Xs0
(2X-2,
x 20
44

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

lol

step-by-step explanation:

answer: it is d

step-by-step explanation: