What is the Slope of the line perpendicular to y = (-2/3)X-20.

Since our line is perpendicular to the function given, we can use that slope to find the slope of our new line.

To find the perpendicular slope, take the negative reciprocal of the original slope (negative and flip the fraction) so the slope of the new line will be -3/2.

y+6=-3/2(x-12)

There's your answer :)

Step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.