A sample of size will be drawn from a population with mean and standard deviation . Use the TI-84 calculator. Part 1 of 2 Your Answer is incorrect Find the probability that will be more than . Round the answer to at least four decimal places. The probability that will be more than is . Part 2 of 2 Your Answer is incorrect Find the percentile of . Round the answer to two decimal places. The percentile is

This question is incomplete, the complete question is;

A sample of size 86 will be drawn from a population with mean 90 and standard deviation 24. Use the TI-84 calculator Part 1 of 2

Find the probability that x will be more than 89. Round the answer to at least four decimal places. The probability that will be more than 89 is Part 2 of 2 Find the 60 percentile of x. Round the answer to two decimal places. The 60 percentile is

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part 1) the probability that x will be more than 89 is 0.6517

part 2) the 60 percentile of x is 90.65

Step-by-step explanation:

Given that;

u = 90, α = 24, n = 86

Part 1 says Find the probability that x will be more than 89

p ( x > 89 ) = p (( x - u)/α√n > (89-90)/24/√86 ))

= p ( z > - 0.39 ) = 1 - p (z ≤ - 0.39  )

from z table, 0.39 → 0.3483

= 1 - 0.3483 = 0.6517

∴ the probability that x will be more than 89 is 0.6517

part 2 says  Find the 60 percentile of x

p( Z < z ) = 0.60

now from the z-table, p(Z < 0.25 ) = 0.60

and we that  x = u + z(α/√n)

x = 90 + 0.25( 24 / √ 86

x = 90.64699 ≈ 90.65

∴  the 60 percentile of x is 90.65

idk

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)