Y-3=2(x+1)
Can you guys please help me solve for y

First, you have to rewrite the question in a way to isolate your Y. This means moving the -3 over to the other side.

Y = 2(x+1) + 3

Now, you should multiply the 2 out in the parenthesis.

Y=2x+2+3

Now, combine like terms! In this case, your like terms are 2 and 3.

Y=2x + 5

Because there are no more like terms, and Y is completely isolated, Y=2x + 5 is your answer!

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)