The equation for a parabola has the form y=ax2+bx+c, where a, b, and c are constants and a≠0. Find an equation for the parabola that passes through the points (−1,8), (2,−4), and (−6,−12).

The equation for the parabola that passes through the points (−1,8), (2,−4), and (−6,−12) is .

Step-by-step explanation:

Let be (−1,8), (2,−4), and (−6,−12) points contained in a parabola, which is represented by a second-order polynomial. To determine the constant of the second-order polynomial, the following system of equations must be solved:

There are several methods for solving this: Equalization, Elimination, Substitution, Determinant and Matrix. The solution of this system is: , and . Hence, the equation for the parabola that passes through the points (−1,8), (2,−4), and (−6,−12) is .

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

the answer is 5/14.

hope this .