As a result of a transfer from one school to another, a boy has to walk one and a half times the distance he was walking from home to school. If he
walks at the same pace, how long will he take to walk to school if he was
taking 43 minutes previously?

Let the distance of school and house is x k m

Then time taken at speed 2.5 km\hr=

2.5

x

hr

And time taken at speed 4 km\hr=

4

x

hr

∴

2.5

x

−

4

x

=

60

12

⇒

10

4x−2.5x

=

5

1

⇒x=3 km

Then the distance of school and house is 3 k m

may this help you

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

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step-by-step explanation: