Calculates the perimeter of a qudrant whose diameter is 14cm

Step-by-step explanation:

By quadrant I presume you mean 1/4 of the circle. The perimeter will be 1/4 of the circle’s circumference plus the length of the two radii that complete the 1/4 section.

C=2 × pi × r = 28 pi

Perimeter = 28 pi +14+14. using 22/7 for pi

22/7 × 28 +28 = 88 + 28 = 116

116 cm is perimeter

Hope my answer will be correct

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.