Oscar rode his bicycle at a rate of 9 mph and then speed up to 16 mph. he rode 30 minutes longer at 9 mph than he did at 16 mph. If he traveled a total of 22 miles, how long did he ride at the slower rate?

t = 0.7 h

The time he rode at a slower speed is 1.2 h

Step-by-step explanation:

-The question involves algebra, to find the time the distance formula is used involving the values of distance, time and speed.

- distance = speed 1 * time 1 + speed 2 * time 2

If Oscar traveled for t minutes at 9mph and it took him 15 minutes longer than when he traveled at 16mph it means that:

speed 1 * time 1 + 30 minutes.

But 30 minutes converted to hours is 0.5 hours

22 miles = 9 * (t + 0.5) + 16 * t

22 = 9t + 4.5 + 16t

17.5 = 25t

17.5 / 25 = t

The answer is: t = 0.7

Checking the value in the equation:

22 miles = 9 * (t + 0.5) + 16 * t

22 = 9 * (0.7 + 0.5) + 16 * 0.7

22 = 9 * 1.2 + 11.2

22 = 10.8 + 11.2

22 = 22

the answer is:

mean: 6

mad: 2.14

just keep asking questions until you have a better understanding.

step-by-step explanation: