Solve the following systems using the substitution method.

Step-by-step explanation:

2x + 8y = 12 Equation 1

x - 2y = 0 Equation 2

Make x the subject in equation 2 and substitute it into equation 1

That's

x = 2y

We have

2(2y) + 8y = 12

4y + 8y = 12

12y = 12

Divide both sides by 12

y = 1

Substitute y = 1 into x = 2y

That's

x = 2(1)

x = 2

The answers are

x + y = 7 Equation 1

2x + y = 5 Equation 2

Make y the subject in equation 1 and substitute it into equation 2

We have

y = x - 7

2x + x - 7 = 5

3x = 7 + 5

3x = 12

Divide both sides by 3

x = 4

Substitute x = 4 into y = x - 7

y = 4 - 7

y = - 3

We have the answers as

y = -1/2 + 1 Equation 1

2x + 3y = 6 Equation 2

From equation 1

y = 1/2

Substitute y = 1/2 into Equation 2

So we have

2x + 3(1/2) = 6

2x + 3/2 = 6

2x = 6 - 3/2

2x = 9/2

Divide both sides by 2

x = 9/4

The answers are

2x - 1/3y = - 9 Equation 1

-3x + y = 15 Equation 2

Make y the subject in equation 2 and substitute it into equation 1

That's

y = 15 + 3x

2x - 1/3( 15 + 3x) = - 9

2x - 5 - x = - 9

x = - 9 + 5

x = - 4

Substitute x = - 4 into y = 15 + 3x

That's

y = 15 + 3(-4)

y = 15 - 12

y = 3

The answers are

Hope this helps you

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.