Use the numerals 1,7,7,7, and 7 to create the number 100

Step-by-step explanation:

What we're basically looking for here are ways to get 100 using these numbers.

My immediate first thought was "can we divide the 7's by some 7's to get 100?"

I know that , so I had the idea to make it . This means that we can use the number 7 four times in the equation .

However, we're still missing a 1 that we need to include. This is easy, we can just multiply by 1.

So in conclusion, we get

Hope this helped!

177 - 77 = 100

Step-by-step explanation:

there are basically 4 7s

77-77 = 00

177 - 77 = 100

hope this helps （＾▽＾）

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.