The sum of 6consecutive integers is 519. What is the third number in this sequence?

The third sequence Integer is 86.

SOLUTION:-

Given:

The sum of 6 consecutive integers is 519.

To find:

The third number in sequence.

Explanation:

Let the first integer be R.

&

6 consecutive Integer is;

R, R+1,R+2,R+3,R+4,R+5

According to the question:

=) R + R+1+R+2+R+3+R+4+R+5= 519

=) 6R + 15 = 519

=) 6R = 519 -15

=) 6R = 504

=) R= 504/6

=) R= 84

Therefore,

Sequence Integer:

1st number is R= 84.

2nd number is R+1= 84 +1 = 85.

3rd number is R+2 = 84 +2 = 86.

4th number is R+3 = 84 +3 = 87.

5th number is R+4 = 84 +4 = 88.

6th number is R+5 = 84 +5 = 89.

Hope this helped.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

the image of (6, 9) under a dilation is (4, 6). the scale factor is