The number of real solutions to the quadratic equ
5a² + 30a + 45 = 0

The answer is 1.

There is one unique real solution, which is x = -3.

Hello, please consider the following.

Thank you

two equal, real solutions

Step-by-step explanation:

The quickest way to determine this is to find the discriminant b^2 - 4ac.  If this determinant (D) is > 0, the quadratic has two different real roots; if + 0, the quadratic has two equal real roots, and if < 0, the quadratic has two imaginary or complex roots.

Here a = 5, b = 30 and c = 45.  The discriminant is

30^2 - 4(5)(45)  =  900 - 900 = 0

and so this quadratic has two equal, real solutions.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47