The half-life of carbon-14 is 5600 years. If a piece of charcoal made from the wood of a tree shows only 72% of the carbon-14 expected in living matter, when did the tree die?

t =2654.01465 year

Step-by-step explanation:

Given that the half-life of carbon-14 is 5600 years and if a piece of charcoal made from the wood of a tree shows only 72% of the carbon-14 expected in living matter.

we know

where y= final amount

a= initial amount

b= growth/decay

t= time elapsed

h= half time

plugging the values we get

taking log on both side

log 0.72 = t/5600 log(1/2)

solving we get t =2654.01465 year

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

9987

step-by-step explanation: