A new youth center is being built in erie . The perimeter of the rectangular playing field is 296 yards. The length of the field is 2 yards less than double the width. What are the dimensions of the playing field?

The dimensions are 50 yards by 98 yards

Step-by-step explanation:

If the width is w, then the length is 2w - 2. Perimeter can be expressed by 2 * (length + width), therefore:

2 * (2w - 2 + w) = 296

2 * (3w - 2) = 296

3w - 2 = 148

3w = 150

w = 50 so 2w - 2 = 2 * 50 - 2 = 98

Step-by-step explanation:

Let the length be l.

Let the width be w.

The perimeter of the rectangle is 296 yards.

Plug in the value for l and P.

Evaluate and solve for w.

The width is 50 yards.

Let w = 50 for l.

Evaluate and solve for l.

The length is 98 yards.

828. all there is to it!

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b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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