3. A ship sails 35 km on a bearing of 042º. a) How far north has it travelled?
b) How far east has it travelled?
4 A ship sails 200 km on a bearing of 243.7°
a) How far south has it travelled?
b) How far west has it travelled?

3 and 4 please

3(a). The ship travelled in north is 26.0 km.

(b). The ship travelled in east is 23.4 km.

4(a). The ship travelled in south is -88.61 km.

(b). The ship travelled in west is -179.29 km.

Step-by-step explanation:

Given that,

(3). Distance = 35 km

Angle = 42°

Let distance in north is y km.

We need to calculate the distance

Using vertical component

Put the value into the formula

Let distance in east is x  km

We need to calculate the distance

Using horizontal component

Put the value into the formula

(4). A ship sails 200 km on a bearing of 243.7°

Let distance in south is y km.

We need to calculate the distance

Using vertical component

Put the value into the formula

Let distance in west is x  km

We need to calculate the distance

Using horizontal component

Put the value into the formula

Hence, 3(a). The ship travelled in north is 26.0 km.

(b). The ship travelled in east is 23.4 km.

4(a). The ship travelled in south is -88.61 km.

(b). The ship travelled in west is -179.29 km.

add the table and i will answer correctly

step-by-step explanation: