1. Find 3 consecutive integers whose sum is 33.

  10, 11, 12

Step-by-step explanation:

For problems involving consecutive integers, I like to consider their average value. For three consecutive integers, their average will be the middle one. It will be ...

  average = sum / (number of numbers) = 33/3 = 11

The middle number is 11, so the numbers are ...

  10, 11, 12

If you want to write an equation, you can let x represent the middle number. Then the other two are x-1 and x+1, and their sum is ...

  (x-1) +(x) +(x+1) = 33 = 3x

  x = 11   ⇒   x-1 = 10, x+1 = 12

ou would have 12 of each