A(n) = -5 + 6(n - 1)a(n)=−5+6(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 5, plus, 6, left parenthesis, n, minus, 1, right parenthesis Find the 12^\text{th}12
th
12, start superscript, start text, t, h, end text, end superscript term in the sequence.

The 12th term is 61

Step-by-step explanation:

I will assume that your a(n) = -5 + 6(n - 1) is correct; the rest is redundant (duplicative, unneeded).

To find the 12th term, substitute 12 for n in the above formula:

a(12) = -5 + 6(12 - 1) = -5 + 6(11) = 66 - 5, or 61

The 12th term is 61

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong