A bank is designing a new branch office and needs to determine how much driveway space to allow for cars waiting for drive-up teller service. How many spaces should be provided to have a 96 percent probability of accommodating all of the waiting cars

This question is incomplete, the complete question is;

A bank is designing a new branch office and needs to determine how much driveway space to allow for cars waiting for drive-up teller service.

The drive-up service will have three tellers and a single waiting line. At another branch of the bank in a similar setting, the average service time for drive-up tellers is four minutes per customer, and average arrival rate is 36 customers per hour. It is expected that the new bank will have similar characteristics.

How many spaces should be provided to have a 96 percent probability of accommodating all of the waiting cars?

Eleven (11) spaces should be provided to have a 96 percent probability of accommodating all of the waiting cars

Step-by-step explanation:

Given that:

the average service time for drive-up tellers is four (4) minutes per customer at each branch

Average number of customers per hour is 36

Therefore for 36 customers,

the branch can give ( 36 / 4 ) = 9, mins each customer

from the question, there is a probability of 96%

so we will calculate on the 9 as mentioned above

96% of 9 = 0.96

0.96 × 9= 8.64

If there are 3 tellers in a single line- , then

8.64 + 3 = 11.64 approximately 11

Therefore Eleven (11) spaces should be provided to have a 96 percent probability of accommodating all of the waiting cars

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step-by-step explanation:

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dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier