"If the average cholesterol level is 194 with a standard deviation of 15, what percentage of children have a cholesterol level lower than 199? Answers are rounded to the nearest whole percent."

63%

Step-by-step explanation:

Given the following :

Average cholesterol level or mean (m) = 194

Standard deviation (sd) = 15

what percentage of children have a cholesterol level lower than 199?

P(X < 199)

Assume a normal distribution :

Find the z-score :

Z = (score - mean) / standard deviation

Score = 199

Z = (199 - 194) / 15

Z = 5 / 15

Z - score = 0.3333

P(Z < 0.33) :

Using the z - table ; 0.33 = 0.6293

P(Z < 0.33) = 0.6293

0.6293 * 100% = 62.93%

= 63% (nearest whole percent)

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: