What answers are contained in this text and where are they? Choose the correct answer below. A. The answers to the Practice exercises are at the bottom of the page and the answers to the selected exercises from the exercise set are in the back of the book. B. The answers to the Practice exercises are in the back of the book and the answers to the selected exercises from the exercise set are at the bottom of the page. C. The answers to the Practice exercises and the answers to the selected exercises from the exercise set are in the back of the book. D. The answers to the Practice exercises are in the answer manual and the answers to the selected exercises from the exercise set are at the bottom of the page.

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step-by-step explanation:

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step-by-step explanation:

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step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt