Factorise: 5(2^n)+2^n+2

2 ( n + 2 ) ( n + 1 2 )

Step-by-step explanation:

coefficient of the first term:  

2 = 2 × 1

coefficient of the last term:  

2 = 2 × 1

coefficient of the middle term (using only the factors above):  

5 = 2 × 2 + 1 × 1

2 n 2 + 5 n + 2 = ( 2 n + 1 ) ( n + 2 )

Alternative method:

Treat the given expression as a quadratic set equal to zero, with the form

a n 2 + b n + c

and use the quadratic formula

− b ± √ b 2 − 4 a c 2 a

This will given solutions

n = − 2  and  n = − 1 2

for a factoring

2 ( n + 2 ) ( n + 1 2 )

Hope this helped

step-by-step explanation:

for the free

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)