What is the slope of the line with points (3, 5) and (8, 2)?

-3/5

Step-by-step explanation:

To find slope we use the formula, slope = (y2-y1)/(x2-x1)

We let (3,5) be the first point so, x1 = 3 and y1 = 5

We let (8,2) be the second point so, x2 = 8 and y2 = 2

Now we plug it in the formula,

slope =  (2-5)/(8-3) = -3/5

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.