I NEED TO FINISH THIS NOW PLZ HELP MEE!!

height of building A = 64 meters

height of building B = 87 meters

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Explanation:

Refer to the diagram below.

I have added points A,B,C,D to help find the heights needed.

Focus on triangle BAC. This is a right triangle with 58 degrees as one of the known acute angles (angle BAC = 58). Also known is the adjacent side AB = 40. The unknown side we're after is side BC

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tan(angle) = opposite/adjacent

tan(angle BAC) = BC/AB

tan(58) = BC/40

40*tan(58) = BC

BC = 40*tan(58)

BC = 64.013381161642

BC = 64 meters approximately

This is the approximate height of building A

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Now focus on triangle DAB

This is another right triangle. The acute angle is now 30 degrees as this is the angle of elevation.

tan(angle) = opposite/adjacent

tan(angle DAB) = DB/AB

tan(30) = DB/40

40*tan(30) = DB

DB = 40*tan(30)

DB = 23.094010767585

DB = 23 meters approximately

Add this onto BC to get

DC = DB+BC

DC = 64+23

DC = 87

Building B has a height of roughly 87 meters

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note: a more accurate value would be

DC = DB+BC

DC = 40*tan(30) + 40*tan(58)

DC = 87.107391929227

but when we round this to the nearest meter, we still get DB = 87

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.