The central angle of sector R is 38° and the central angle of sector Q is 39°. What is the probability that the spinner does not land on Q or R? P Q R S T U

0.786

Step-by-step explanation:

Here i would assume that:

Sector R and Sector Q do not have any sections in common.

Then, the probability that the spinner does not land on Q or R, is equal to the probability where the spinner does not land in a specified section of:

38° + 39° = 77°.

Now, the total section off the spinner is 360°.

If we remove those 77°, we have a section of:

360° - 77° = 283°

So we have 283° where the spinner CAN land on.

Then the probability that the spinner does NOT land on R or Q is equal to the quotient between the section of the spinner that is not R or Q, and the total section of the spinner"

P = 283/360 = 0.786

So the probability is 0.786

step-by-step explanation:

3024 rhe base is what up in worry about

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w