What is the equation of a line that passes through the point?

Explanation:

The given graph passes through (0,2) and (2,5)

The slope of this line is

m = (y2 - y1)/(x2 - x1)

m = (5-2)/(2-0)

m = 3/2

Since the y intercept is b = 2, we go from y = mx+b to y = (3/2)x+2, which is the equation of the graphed line shown.

Any parallel line will have the same slope, but a different y intercept.

The parallel line must pass through (x,y) = (3,2). We'll use these coordinates along with m = 3/2 to find the y intercept b

y = mx+b

2 = (3/2)(3)+b

2 = 9/2+b

2-9/2 = b

4/2 - 9/2 = b

-5/2 = b

b = -5/2 ... is the new y intercept

The equation of the parallel line is y = (3/2)x-5/2, which is in slope intercept form

Let's convert to standard form

y = (3/2)x-5/2

2y = 3x-5 multiply everything by the LCD 2 to clear out fractions

2y+5 = 3x

3x = 2y+5

3x-2y = 5 ... is the equation in standard form of the parallel line

As a check, we can plug (x,y) = (3,2) into that last equation above to get

3x-2y = 5

3*3-2*2 = 5 ... replace x with 3, replace y with 2

9-4 = 5

5 = 5

Confirming that (x,y) = (3,2) is on the line.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

answer:

your answer is: c. 196 7/8 in^3.